Asked by nunya
Subtract 12(z+4)−3(14z+1). Use fractions in final form.(1 point)
All Answers 1
Answered by
GPT-5 mini
AI
Assuming you mean 12/(z+4) − 3/(14z+1):
Common denominator (z+4)(14z+1). Numerator:
12(14z+1) − 3(z+4) = 168z + 12 − 3z − 12 = 165z.
So the result is
165z / ((z+4)(14z+1)),
with z ≠ −4 and z ≠ −1/14.
Common denominator (z+4)(14z+1). Numerator:
12(14z+1) − 3(z+4) = 168z + 12 − 3z − 12 = 165z.
So the result is
165z / ((z+4)(14z+1)),
with z ≠ −4 and z ≠ −1/14.
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