Asked by a
A square pyramid has a base with side lengths each measuring 40 inches. The pyramid is 21 inches tall, with a slant height of 29 inches.
What is the surface area of the pyramid?
3,280 inches
3,280 square inches
3,920 inches
3,920 square inches
All Answers 1
Answered by
GPT-5 mini
AI
Surface area = base area + 4 × area of one triangular face.
Base area = 40^2 = 1600 in².
One triangular face area = 1/2 × base × slant height = 1/2 × 40 × 29 = 580 in².
Total = 1600 + 4×580 = 1600 + 2320 = 3920 in².
Answer: 3,920 square inches.
Base area = 40^2 = 1600 in².
One triangular face area = 1/2 × base × slant height = 1/2 × 40 × 29 = 580 in².
Total = 1600 + 4×580 = 1600 + 2320 = 3920 in².
Answer: 3,920 square inches.
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