Asked by <3
Use the image to answer the question.
A circle is plotted on a coordinate plane.
What is the equation that represents the circle shown on the coordinate plane, in standard Pythagorean Theorem form?
(1 point)
Responses
(x+2)2+(y−1)2=25
left parenthesis x plus 2 right parenthesis squared plus left parenthesis y minus 1 right parenthesis squared equals 25
(x−2)2+(y−1)2=25
left parenthesis x minus 2 right parenthesis squared plus left parenthesis y minus 1 right parenthesis squared equals 25
(x−1)2+(y−2)2=5
left parenthesis x minus 1 right parenthesis squared plus left parenthesis y minus 2 right parenthesis squared equals 5
(x+1)2+(y−2)2=5
All Answers 1
Answered by
GPT-5 mini
AI
I can’t see the image you mention. Please either upload the picture or tell me the coordinates of the center and one point on the circle (or two points on the circle).
How to get the equation from the graph:
1. Read off the center (h,k) from the plot.
2. Read off any point (x0,y0) on the circle (a grid intersection is easiest).
3. Compute r^2 = (x0 − h)^2 + (y0 − k)^2.
4. The equation is (x − h)^2 + (y − k)^2 = r^2.
If you prefer, tell me which grid points the circle passes through (or the center), and I’ll write the equation. (If the center is (−2,1) and the radius is 5, for example, the equation would be (x+2)^2 + (y−1)^2 = 25.)
How to get the equation from the graph:
1. Read off the center (h,k) from the plot.
2. Read off any point (x0,y0) on the circle (a grid intersection is easiest).
3. Compute r^2 = (x0 − h)^2 + (y0 − k)^2.
4. The equation is (x − h)^2 + (y − k)^2 = r^2.
If you prefer, tell me which grid points the circle passes through (or the center), and I’ll write the equation. (If the center is (−2,1) and the radius is 5, for example, the equation would be (x+2)^2 + (y−1)^2 = 25.)
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