Question

A circle is drawn on a coordinate plane with the center point at (5,−3)
and a radius of 6. Derive the equation of the circle in standard form, using the given information and the Pythagorean Theorem.(1 point)
Responses

(x+5)2+(y−3)2=36
left parenthesis x plus 5 right parenthesis squared plus left parenthesis y minus 3 right parenthesis squared equals 36

(x−3)2+(y−5)2=36
left parenthesis x minus 3 right parenthesis squared plus left parenthesis y minus 5 right parenthesis squared equals 36

(x−5)2+(y+3)2=36
left parenthesis x minus 5 right parenthesis squared plus left parenthesis y plus 3 right parenthesis squared equals 36

(x+3)2+(y−5)2=36

Answer 1

(x−5)² + (y+3)² = 36

Reason: Standard form is (x−h)²+(y−k)²=r². With center (h,k)=(5,−3) and r=6, we get (x−5)²+(y+3)²=36.