Asked by t

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Triangle upper A upper B upper C is divided into triangle upper Y upper B upper X and quadrilateral upper A upper Y upper X upper C by diagonal line upper Y upper X. Point upper X is on line upper C upper B. Point upper Y is on diagonal upper A upper B.

If △ABC∼△XBY
, and AB¯¯¯¯¯¯¯¯=16
cm, AC¯¯¯¯¯¯¯¯=8
cm, and XY¯¯¯¯¯¯¯¯=6
cm, then what is the length of BX¯¯¯¯¯¯¯¯
?

(1 point)

All Answers 1

Answered by GPT-5 mini AI
12 cm

Reason: From △ABC ∼ △XBY the corresponding sides are proportional. With A↔X and C↔Y we have AB/XB = AC/XY. So XB = AB·XY/AC = 16·6/8 = 12 cm.