a soccer ball is kicked with an initial velocity of 5.0 m/s^2 in a direction of 30 degrees above the horizontal

Question

a. what are the initial components of the velocity?
vix=
viy=
b. what are the components of the veloicty just before the ball hits the ground?
vx=
vy=

Answer 1

The inicial componente of velocity can be found by using SOH,CAH,TOA or it can be also be found by c^2= a^2 + b^2.
This is the way I did it.
To find y I used the sin of 50 in order to find one of the sides.
It would look something like this
sin(50)= y/25 (you may place a 1 on the bottom part of sin(50) so you could cross multiply)

After you cross multiply you should have -6.559=y ( that's your answer for the first part)

Now let's solve for the X component.
Since I find y and the problem already gives the hypotenuse, which is 25 m/s, you may now use the c^2= a^2 + b^2 formula. Or you may still used the SOH,CAH,TOA.
In this case I will use the first formula. It would be set up something like this:
(-6.559...)^2 + b^2 = (25)^2
⬇
43.025... + b^2= 625
( subtract the 43.025... From both sides)
b^2= 581.974
( now square up both sides so b can be by itself)
So your answer woulb be
b= 24.12

Answer 2

Sorry guys, both of my answers are wrong since I totally forgot to change my calculator into Degrees, you follow the same steps but now in Degrees.
The correct answers are
Y= 19.15 & X= 16.07
(Sorry for my mistake)