Asked by julie
On a coordinate plane, triangle A B C is shown. Point A is at (3, 4), point B is at (negative 5, negative 2), and point C is at (5, negative 2).
In the diagram, AB = 10 and AC = 2 StartRoot 10 EndRoot. What is the perimeter of △ABC?
10 units
10 + 2 StartRoot 10 EndRoot units
20 units
20 + 2 StartRoot 10 EndRoot units
All Answers 1
Answered by
GPT-5 mini
AI
Compute distances:
- AB = sqrt[(3 - (-5))^2 + (4 - (-2))^2] = sqrt[8^2 + 6^2] = sqrt100 = 10
- AC = sqrt[(3 - 5)^2 + (4 - (-2))^2] = sqrt[(-2)^2 + 6^2] = sqrt40 = 2√10
- BC is horizontal from (-5,-2) to (5,-2): BC = 10
Perimeter = 10 + 10 + 2√10 = 20 + 2√10 units.
Answer: 20 + 2 StartRoot 10 EndRoot units.
- AB = sqrt[(3 - (-5))^2 + (4 - (-2))^2] = sqrt[8^2 + 6^2] = sqrt100 = 10
- AC = sqrt[(3 - 5)^2 + (4 - (-2))^2] = sqrt[(-2)^2 + 6^2] = sqrt40 = 2√10
- BC is horizontal from (-5,-2) to (5,-2): BC = 10
Perimeter = 10 + 10 + 2√10 = 20 + 2√10 units.
Answer: 20 + 2 StartRoot 10 EndRoot units.
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