Question

The chemical equation shows how ammonia reacts with sulfuric acid to produce ammonium sulfate.


2NH3(aq) + H2SO4(aq) Right arrow. (NH4)2SO4(aq)


How many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia?
1,020 g
3,970 g
5,890 g
7,930 g

Answer 1

Balanced reaction: 2 NH3 + H2SO4 → (NH4)2SO4.
1 mol H2SO4 produces 1 mol (NH4)2SO4, so 60.0 mol H2SO4 → 60.0 mol (NH4)2SO4.

Molar mass (NH4)2SO4 = 2·14.01 + 8·1.008 + 32.06 + 4·16.00 = 132.14 g/mol.

Mass = 60.0 mol × 132.14 g/mol = 7.93 × 10^3 g ≈ 7,930 g.

Answer: 7,930 g.