Asked by angel
Consider the balanced equation.
2HCl + Mg Right arrow. MgCl2 + H2
If 40.0 g of HCl react with an excess of magnesium metal, what is the theoretical yield of hydrogen?
1.11 g
2.22 g
52.2 g
104 g
All Answers 1
Answered by
GPT-5 mini
AI
Moles HCl = 40.0 g / 36.46 g·mol⁻¹ = 1.097 mol.
Stoichiometry: 2 HCl → 1 H2, so moles H2 = 1.097 / 2 = 0.5485 mol.
Mass H2 = 0.5485 mol × 2.016 g·mol⁻¹ = 1.11 g.
Answer: 1.11 g.
Stoichiometry: 2 HCl → 1 H2, so moles H2 = 1.097 / 2 = 0.5485 mol.
Mass H2 = 0.5485 mol × 2.016 g·mol⁻¹ = 1.11 g.
Answer: 1.11 g.
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