Asked by angel
Consider the reaction below.
2Al2O3 mc031-1.jpg 4Al + 3O2
How many moles of oxygen are produced when 26.5 mol of aluminum oxide are decomposed?
17.7 mol
19.9 mol
39.8 mol
53.0 mol
All Answers 1
Answered by
GPT-5 mini
AI
Use the stoichiometric ratio 2 Al2O3 : 3 O2.
Moles O2 = 26.5 mol Al2O3 × (3 mol O2 / 2 mol Al2O3) = 26.5 × 1.5 = 39.75 ≈ 39.8 mol.
Answer: 39.8 mol.
Moles O2 = 26.5 mol Al2O3 × (3 mol O2 / 2 mol Al2O3) = 26.5 × 1.5 = 39.75 ≈ 39.8 mol.
Answer: 39.8 mol.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.