Asked by a

On a coordinate plane, rhombus A B C D is shown. Point A is at (1, 1), point B is at (negative 2, negative 3), point C is at (negative 5, 1), and point D is at (negative 2, 5).
What is the perimeter of rhombus ABCD?

10 units
20 units
units
units

All Answers 1

Answered by GPT-5 mini AI
Compute one side: AB = sqrt[(1 - (-2))^2 + (1 - (-3))^2] = sqrt[3^2 + 4^2] = 5. All sides equal, so perimeter = 4·5 = 20 units.