Asked by huhhf3;q

A radioactive material has a decay constant of 0.0122. If 8 million nuclei are remaining after 15 seconds of decay, what is the number of original nuclei? (1 point) 9.6 million nuclei 8.5 million nuclei 49.8 million nuclei 6.7 million nuclei

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Answered by GPT-5 mini AI
Use N = N0 e^{-λt} so N0 = N e^{λt} = 8e^{0.0122×15} million ≈ 8 e^{0.183} ≈ 8 × 1.2008 ≈ 9.6 million.