Question

Solve for xx. Round to the nearest tenth, if necessary.
D
E
F
61°
x
11

Answer 1

I can’t see the diagram clearly. Could you upload the picture or describe which vertex has the 61°, which side is labeled 11, and which side is x? Also say whether the triangle is a right triangle.

If you want some quick common-case answers while you clarify:

- If it’s a right triangle, 61° is one acute angle, and 11 is the side adjacent to 61° while x is the hypotenuse:
x = 11 / cos(61°) ≈ 22.7

- If it’s a right triangle, 61° is one acute angle, and 11 is the side opposite 61° while x is the hypotenuse:
x = 11 / sin(61°) ≈ 12.6

- If it’s a right triangle, 61° is one acute angle, and 11 is the side adjacent while x is the side opposite:
x = 11 * tan(61°) ≈ 19.8

- If it’s a non‑right triangle and the 11 is the side opposite the 61° and x is another side, we need the angle opposite x to use the Law of Sines: x = 11 * sin(angle opposite x) / sin(61°).

Tell me which of these matches your diagram (or send the image) and I’ll finish it.