Question

It takes 40 mL of 0.10 M of hydrochloric acid (HCl) to neutralize 50 mL of sodium hydroxide (NaOH) for the following chemical reaction:

HCl + NaOH → NaCl + H2O

The concentration of sodium hydroxide is_____Blank.

(1 point)
Responses

0.04 M
0.04 M

0.125 M
0.125 M

0.10 M
0.10 M

0.08 M

Answer 1

Moles HCl = 0.10 M × 0.040 L = 0.0040 mol.
Moles NaOH = 0.0040 mol (1:1 reaction).
[NaOH] = 0.0040 mol / 0.050 L = 0.08 M.

Answer: 0.08 M.