Question

If you dilate triangle ABC to form X'Y'Z' using a magnitude of 2 and a center of dilation at (2,0), what arethe coordinates of the dilated triangle?
(1 point)
A' (0,12), B' (4,0), C' (10,8)
A' (2,12), B' (6,0), C' (12,8)
A' (1.5,3), B' (2.5,0), C' (4,2)
A' (.5,3), B' (1.5,0), C' (3,2)

Answer 1

Use P' = center + 2(P − center). With center (2,0) this gives P' = (2x − 2, 2y).

If A(1,6), B(3,0), C(6,4) (the original triangle), then
A' = (2·1 − 2, 2·6) = (0,12),
B' = (2·3 − 2, 2·0) = (4,0),
C' = (2·6 − 2, 2·4) = (10,8).

So the correct choice is: A' (0,12), B' (4,0), C' (10,8).