Question

4 number lines going from negative 6 to positive 10. Graph A has an open circle at 2 with everything shaded to the right. Graph B has an open circle at negative 2 with everything shaded to the right. Graph C has an open circle at 0 with everything shaded to the left. Graph D has an open circle at negative 2 with everything shaded to the left.
Which number line shows the solution to
11x + 14 < –8?

Answer 1

Solve: 11x + 14 < −8
11x < −22 (subtract 14)
x < −22/11 = −2 (divide by 11)

Because the inequality is strict, use an open circle at −2 and shade to the left. That is Graph D.