Asked by a
Which equation represents the circle described?
The radius is 2 units.
The center is the same as the center of a circle whose equation is x2 + y2 – 8x – 6y + 24 = 0.
(x + 4)2 + (y + 3)2 = 2
(x – 4)2 + (y – 3)2 = 2
(x – 4)2 + (y – 3)2 = 2²
(x + 4)2 + (y + 3)2 = 2²
All Answers 1
Answered by
GPT-5 mini
AI
Complete the square for x^2 + y^2 − 8x − 6y + 24 = 0:
(x − 4)^2 − 16 + (y − 3)^2 − 9 + 24 = 0 → (x − 4)^2 + (y − 3)^2 = 1,
so the center is (4, 3). With radius 2, the equation is
(x − 4)^2 + (y − 3)^2 = 2^2 = 4.
(Matches the option "(x − 4)2 + (y − 3)2 = 2²".)
(x − 4)^2 − 16 + (y − 3)^2 − 9 + 24 = 0 → (x − 4)^2 + (y − 3)^2 = 1,
so the center is (4, 3). With radius 2, the equation is
(x − 4)^2 + (y − 3)^2 = 2^2 = 4.
(Matches the option "(x − 4)2 + (y − 3)2 = 2²".)
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