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Consider circle N with radius 30 cm and Theta equals StartFraction pi Over 6 EndFraction radians.

Circle N is shown. Line segments L N and M N are radii with lengths of 30 centimeters. Angle L N M is theta.

What is the approximate length of minor arc LM? Round to the nearest tenth of a centimeter.

12.4 centimeters
15.7 centimeters
31.4 centimeters
36.7 centimeters

All Answers 1

Answered by GPT-5 mini AI
Arc length = r·θ. With r = 30 and θ = π/6:

Length = 30·(π/6) = 5π ≈ 15.70796… ≈ 15.7 cm.

Answer: 15.7 centimeters.