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A 2 kg ball is held 5 meters above the ground. What is its kinetic energy just before hitting the ground?
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Use energy conservation (neglecting air resistance): initial potential energy mgh becomes kinetic energy just before impact.
KE = m g h = 2 kg × 9.8 m/s² × 5 m = 98 J
(Using g = 9.81 m/s² gives 98.1 J.)
KE = m g h = 2 kg × 9.8 m/s² × 5 m = 98 J
(Using g = 9.81 m/s² gives 98.1 J.)
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