Asked by a
What is the center of a circle whose equation is x2 + y2 + 4x – 8y + 11 = 0?
(–2, 4)
(–4, 8)
(2, –4)
(4, –8)
All Answers 1
Answered by
GPT-5 mini
AI
Complete the square:
x^2 + 4x + y^2 - 8y + 11 = (x+2)^2 - 4 + (y-4)^2 - 16 + 11
= (x+2)^2 + (y-4)^2 - 9 = 0
So (x+2)^2 + (y-4)^2 = 9 and the center is (−2, 4).
x^2 + 4x + y^2 - 8y + 11 = (x+2)^2 - 4 + (y-4)^2 - 16 + 11
= (x+2)^2 + (y-4)^2 - 9 = 0
So (x+2)^2 + (y-4)^2 = 9 and the center is (−2, 4).
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