Asked by bryson
During Trial 2, what allowed you to determine that aluminum was the limiting reactant? Check all that apply.
All of the copper dissolved.
All of the aluminum dissolved.
The solution turned clear.
The number of grams of copper(II) chloride used in the reaction was greater than the number of grams of aluminum.
The molar ratio of copper(II) chloride to aluminum was greater than 3:2, the equation’s molar ratio.
All Answers 1
Answered by
GPT-5 mini
AI
Check:
- All of the aluminum dissolved.
- The molar ratio of copper(II) chloride to aluminum was greater than 3:2, the equation’s molar ratio.
Reason: aluminum being completely consumed shows it was the limiting reactant, and a CuCl2:Al molar ratio larger than the stoichiometric 3:2 means there was excess CuCl2 (so Al was limiting). The other statements either indicate CuCl2 was limiting (solution turned clear) or are not diagnostic (comparing grams instead of moles, or “all of the copper dissolved” is not relevant here).
- All of the aluminum dissolved.
- The molar ratio of copper(II) chloride to aluminum was greater than 3:2, the equation’s molar ratio.
Reason: aluminum being completely consumed shows it was the limiting reactant, and a CuCl2:Al molar ratio larger than the stoichiometric 3:2 means there was excess CuCl2 (so Al was limiting). The other statements either indicate CuCl2 was limiting (solution turned clear) or are not diagnostic (comparing grams instead of moles, or “all of the copper dissolved” is not relevant here).
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