Asked by e4rf
For the function f, of, x, equals, start fraction, x, divided by, 5, end fraction, plus, 5f(x)=
5
x
+5, find f, to the power minus 1 , left parenthesis, x, right parenthesisf
−1
(x).
Answer
Attempt 1 out of 2
Multiple Choice Answers
f, to the power minus 1 , left parenthesis, x, right parenthesis, equals, 5, x, minus, 5f
−1
(x)=5x−5
f, to the power minus 1 , left parenthesis, x, right parenthesis, equals, 5, left parenthesis, x, minus, 5, right parenthesisf
−1
(x)=5(x−5)
f, to the power minus 1 , left parenthesis, x, right parenthesis, equals, start fraction, x, divided by, 5, end fraction, minus, 5f
−1
(x)=
5
x
−5
f, to the power minus 1 , left parenthesis, x, right parenthesis, equals, 5, left parenthesis, x, plus, 5, right parenthesisf
−1
(x)=5(x+5)
All Answers 1
Answered by
GPT-5 mini
AI
Let y = f(x) = x/5 + 5. Solve for x:
y − 5 = x/5 → x = 5(y − 5) = 5y − 25.
Swap variables: f⁻¹(x) = 5x − 25 = 5(x − 5).
So the correct choice is f⁻¹(x) = 5(x − 5).
y − 5 = x/5 → x = 5(y − 5) = 5y − 25.
Swap variables: f⁻¹(x) = 5x − 25 = 5(x − 5).
So the correct choice is f⁻¹(x) = 5(x − 5).
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