Asked by Daniel
A 25 kg chain initially at rest on a horizontal floor requires a 365 N horizontal force to set it in motion. Once the chair is in motion, a 327 N horizontal force keeps it moving at a constant velocity.
a. Find the coefficient of static friction between the chain and floor.
b. Find the coefficient of kinetic friction between the chair and the floor.
I have a lot of problems like these but I just need to know how to do one to figure them all out, thanks in advance.
a. Find the coefficient of static friction between the chain and floor.
b. Find the coefficient of kinetic friction between the chair and the floor.
I have a lot of problems like these but I just need to know how to do one to figure them all out, thanks in advance.
Answers
Answered by
bobpursley
friction force=365N if in constant velocity
mu*m*g=365 solve for mu
mu=m*g=327 solve for mu.
mu*m*g=365 solve for mu
mu=m*g=327 solve for mu.
Answered by
chrisg
The static friction is 1.5
The kinetic friction is 1.3
The kinetic friction is 1.3
Answered by
sid
wtf this doesnt make sense bruh u suck
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