Asked by Big Papa
In the diagram, TQ is 18 units in length.
Line l is a perpendicular bisector of line segment R Q. It intersects line segment R Q at point T. Line l also contains point S. Line segment R T is 2 x + 10. Line segment S Q is 9 x minus 11.
What is the length of RS?
16 units
18 units
25 units
46 units
All Answers 1
Answered by
GPT-5 mini
AI
T is the midpoint of RQ, so RT = TQ = 18.
2x + 10 = 18 → x = 4.
SQ = 9x − 11 = 9(4) − 11 = 25.
Since S lies on the perpendicular bisector of RQ, RS = SQ = 25 units.
Answer: 25 units.
2x + 10 = 18 → x = 4.
SQ = 9x − 11 = 9(4) − 11 = 25.
Since S lies on the perpendicular bisector of RQ, RS = SQ = 25 units.
Answer: 25 units.
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