Question

A 16.5 cm3 bubble under the ocean at 2.1 atm and 12.5oC surfaces to 1.0 atm and 22.1oC. What is the new volume (in cm3)?
i used (p1)(V1)/T1=(P2)(V2)/T2

(2.1)(.0165)/285.65=(1)(V2)/295.25
THE ANSWER I GOT IS .0335

i changed 16.5 to liters which is why its .0165