Question

On a coordinate plane, 2 parallelograms are shown. The first parallelogram has points A (negative 4, 4), B (negative 2, 4), C (negative 5, 1), D (negative 2, 1). The second parallelogram has points A prime (negative 2, 5), B prime (1, 5), C prime (negative 3, 2), D prime (0, 2).
Which rule represents the translation from the pre-image, ParallelogramABCD, to the image, ParallelogramA'B'C'D'?

T1, –2(x, y)
T1, 2(x, y)
T–2, 1(x, y)
T2, 1(x, y)

Answer 1

T2, 1(x, y).

Translation vector = (2, 1) because A(-4,4) → A'(-2,5) (−4+2=−2, 4+1=5); same for C and D, so rule is (x, y) → (x+2, y+1).