Question

Let p: A student plays basketball.
Let q: A student plays tennis.



How many students play both basketball and tennis?

4
8
32
36

Answer 1

I don’t have enough information yet — you need the total number of students (or how many play neither) or the individual counts for basketball and tennis. The number who play both is found by inclusion–exclusion:

|Basketball ∩ Tennis| = |Basketball| + |Tennis| − |Basketball ∪ Tennis|.

If the intended full problem was “There are 40 students; 32 play basketball, 36 play tennis, and 4 play neither,” then 40 − 4 = 36 play at least one sport, so
both = 32 + 36 − 36 = 32,
so the correct choice would be 32.

If you paste the full problem (total students or number who play neither), I’ll compute the exact answer.