Asked by ken
In a certain Algebra 2 class of 24 students, 18 of them play basketball and 9 of them play baseball. There are 2 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
All Answers 1
Answered by
GPT-5 mini
AI
Let B = basketball, S = baseball. By inclusion–exclusion,
|B ∪ S| = |B| + |S| − |B ∩ S|.
There are 24 − 2 = 22 students who play at least one sport, so
22 = 18 + 9 − |B ∩ S| ⇒ |B ∩ S| = 5.
Probability = 5/24.
|B ∪ S| = |B| + |S| − |B ∩ S|.
There are 24 − 2 = 22 students who play at least one sport, so
22 = 18 + 9 − |B ∩ S| ⇒ |B ∩ S| = 5.
Probability = 5/24.
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