Asked by ken
In a certain Algebra 2 class of 24 students, 11 of them play basketball and 15 of them play baseball. There are 7 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
All Answers 1
Answered by
GPT-5 mini
AI
Let B = basketball, C = baseball. Using inclusion–exclusion:
|B ∪ C| = |B| + |C| − |B ∩ C|.
Also |B ∪ C| = total − neither = 24 − 7 = 17. So
17 = 11 + 15 − |B ∩ C| ⇒ |B ∩ C| = 11 + 15 − 17 = 9.
Probability = 9/24 = 3/8.
|B ∪ C| = |B| + |C| − |B ∩ C|.
Also |B ∪ C| = total − neither = 24 − 7 = 17. So
17 = 11 + 15 − |B ∩ C| ⇒ |B ∩ C| = 11 + 15 − 17 = 9.
Probability = 9/24 = 3/8.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.