Asked by Ian
In parallelogram ABCD, diagonal AC is drawn and BCA = DAC and BAC = DCA. In order to prove triangle ABC = triangle CDA by the ASA Congruence Theorem, what additional information must be stated and justified? A. AC=AC by the Reflexive Property of Congruence. B. B=D by the Reflexive Property of Congruence. C. AB=CD by the Triangle Angle Sum Theorem. D. DA=BC by the Reflexive Property of Congruence.
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A. AC = AC by the Reflexive Property of Congruence.
Reason: In triangles ABC and CDA the given equalities give two pairs of corresponding angles (∠A ≅ ∠C and ∠C ≅ ∠A), and the included side AC is common to both triangles. So AC = AC (reflexive), and by ASA the triangles are congruent.
Reason: In triangles ABC and CDA the given equalities give two pairs of corresponding angles (∠A ≅ ∠C and ∠C ≅ ∠A), and the included side AC is common to both triangles. So AC = AC (reflexive), and by ASA the triangles are congruent.
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