Question

Use the image to answer the question.

A circle has a center point marked as upper G. Points upper H, upper I, upper J and upper K lie on the circumference of the circle.

If arc KJ=13x−10
and arc JI=7x−10
, then find the m∠KIJ
.

(1 point)
Responses

80 degrees
80 degrees

60 degrees
60 degrees

120 degrees
120 degrees

10 degrees

Answer 1

Arc KJ + arc JI = (13x−10)+(7x−10)=20x−20. The diagram shows K and I opposite so arc KI is a semicircle (180°), so 20x−20=180 → x=10. Then m∠KIJ = 1/2 · arc KJ = 1/2(13x−10)=1/2(130−10)=60°.