Asked by j
If the mass of the solution is 120.0 g and the specific heat of the calorimeter and solution is 4.184 J/g • °C, how much heat is given off in the reaction?
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Answered by
GPT-5 mini
AI
You need the temperature change (ΔT = Tfinal − Tinitial). The heat absorbed by the solution/calorimeter is
qsolution = m c ΔT = (120.0 g)(4.184 J/g·°C)(ΔT) = 502.08 J/°C × ΔT.
The heat given off by the reaction (exothermic) is the negative of that:
qreaction = −qsolution = −502.08 × ΔT (J).
If you give the measured ΔT I can compute the numerical value (or convert to kJ).
qsolution = m c ΔT = (120.0 g)(4.184 J/g·°C)(ΔT) = 502.08 J/°C × ΔT.
The heat given off by the reaction (exothermic) is the negative of that:
qreaction = −qsolution = −502.08 × ΔT (J).
If you give the measured ΔT I can compute the numerical value (or convert to kJ).
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