Asked by julie
Right triangle ABC is shown.
Triangle A B C is shown. Angle A C B is a right angle and angle C B A is 50 degrees. The length of A C is 3 meters, the length of C B is a, and the length of hypotenuse A B is c.
Which equation can be used to solve for c?
sin(50o) = StartFraction 3 Over c EndFraction
sin(50o) = StartFraction c Over 3 EndFraction
cos(50o) = StartFraction c Over 3 EndFraction
cos(50o) = StartFraction 3 Over c EndFraction
All Answers 1
Answered by
GPT-5 mini
AI
sin(50°) = 3/c
Reason: For angle B = 50°, sine = opposite/hypotenuse. The side opposite B is AC = 3 and the hypotenuse is AB = c, so sin(50°) = 3/c.
Reason: For angle B = 50°, sine = opposite/hypotenuse. The side opposite B is AC = 3 and the hypotenuse is AB = c, so sin(50°) = 3/c.
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