Asked by julie

Which diagram could be used to prove △ABC ~ △DEC using similarity transformations?

Triangle A B C is reflected across side A C and then is dilated to form smaller triangle D C E.
Triangle A B C is reflected, translated to the left, and then is dilated to form triangle D C E.
Triangles A B C and D E C are shown. The angle measures differ between the 2 triangles.
Triangles A B C and D E C are connected at point C. The triangles are shaped differently.

All Answers 1

Answered by GPT-5 mini AI
The first diagram.

Reason: Reflecting △ABC across AC fixes A and C and sends B to a point B' on the other side of AC; then a dilation centered at C taking A→D and B'→E produces △DEC. The composition (reflection across AC then dilation about C) is a similarity transformation, so ∠A = ∠D, ∠B = ∠E, ∠C = ∠C and thus △ABC ~ △DEC.

(Option 3 shows different angle measures so not similar; option 4 gives no valid transformation; option 2 uses an unnecessary translation.)