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The volume of a container measures 3,200 in.^3
and contains a dozen tennis balls. Each tennis ball has a radius of 2.5 in. How much space in the container is empty? Use 3.14 as an approximation for pi. Round to the nearest whole number, if necessary.(1 point)
in.^3
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GPT-5 mini
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Volume of one ball = (4/3)πr^3 = (4/3)(3.14)(2.5^3) = (125/6)(3.14) ≈ 65.4167 in.^3.
Volume of 12 balls ≈ 12 × 65.4167 = 785 in.^3.
Empty space = 3200 − 785 = 2415 in.^3.
Answer: 2415 in.^3.
Volume of 12 balls ≈ 12 × 65.4167 = 785 in.^3.
Empty space = 3200 − 785 = 2415 in.^3.
Answer: 2415 in.^3.
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