Question

A bag contains one red pen, four black pens, and three blue pens. Two pens are randomly chosen from the bag and are not replaced.

To the nearest hundredth, what is the probability that a black pen is chosen first and then another black pen is chosen?

0.02
0.19
0.21
0.25

Answer 1

There are 8 pens total. P(first black) = 4/8 = 1/2. Given that, P(second black) = 3/7. So the probability = (1/2)*(3/7) = 3/14 ≈ 0.21.

Answer: 0.21