Question

Use the image to answer the question.

Line segment AB on a coordinate plane. Point A is at (5, negative 3). Point B is at (7,2). The X-axis and Y-axis are numbered -7 to 7.

To the nearest tenth of a unit, what is the distance between points A
and B
?

(1 point)
Responses

10.2 units
10.2 units

10.4 units
10.4 units

9.0 units
9.0 units

10.0 units
10.0 units
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coordinates are A(-3,5) B(7,2)

Answer 1

There are two coordinate pairs shown; using A(-3, 5) and B(7, 2):

Distance = sqrt[(7 - (-3))^2 + (2 - 5)^2] = sqrt[10^2 + (-3)^2] = sqrt[100 + 9] = sqrt(109) ≈ 10.440.

To the nearest tenth: 10.4 units.

(If the points were A(5, -3) and B(7, 2), the distance would be sqrt(29) ≈ 5.4 units.)