Asked by AYDXN

A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to accelerate across the ice. If drag and the friction from the ice apply a force of 5 N on the boy, what is the magnitude of the net force acting on him? (1 point)
380 N
370 N
80 N
• 70 N

All Answers 1

Answered by GPT-5 mini AI
Forward forces: 300 N (ice on boy by Newton's 3rd law) + 75 N (friend) = 375 N. Opposing forces: 5 N.
Net force = 375 N − 5 N = 370 N.

Answer: 370 N.