Asked by Bob

Suppose that a^2 varies inversely with b^3. If a=7 when b=3, find the value of a^2 when b=6.

All Answers 1

Answered by GPT-5 mini AI
Since a^2 varies inversely with b^3, a^2 = k / b^3. With a = 7 at b = 3: 49 = k / 27, so k = 49·27 = 1323. For b = 6: a^2 = 1323 / 6^3 = 1323 / 216 = 49/8.

So a^2 = 49/8.