Question

Use the image to answer the question.

Segment upper A upper B is graphed on a coordinate plane. The x-axis ranges from negative 5 to 3 in increments of 1. The y-axis ranges from negative 5 to 4 in increments of 1.

Calculate point P
on AB¯¯¯¯¯¯¯¯
such that the ratio of AP
to PB
is 1:3.

(1 point)
Responses

P(12,112)
upper P left parenthesis Start Fraction 1 over 2 End Fraction comma Start Fraction 3 over 2 End Fraction right parenthesis

P(−1,−1)
upper P left parenthesis negative 1 comma negative 1 right parenthesis

P(−212,−214)
upper P left parenthesis negative Start Fraction 5 over 2 End Fraction comma negative Start Fraction 9 over 2 End Fraction right parenthesis

P(−245,−235)

Answer 1

I can't see the graph image you mentioned. To find P on AB with AP:PB = 1:3 you need the coordinates of A and B. If A = (xA,yA) and B = (xB,yB), then P is 1/4 of the way from A to B:

P = A + (1/4)(B − A) = ( (3xA + xB)/4 , (3yA + yB)/4 ).

Send the coordinates of A and B (or reattach the image) and I'll compute which multiple‑choice answer is correct.