Question
A toboggan (with a mass of 15.0 kg) is being pulled by two people who are each holding their own rope, horizontally with an angle 35 degrees off the direction of travel. They are each pulling with a force of 40.0 N, against a friction force of 20.0 N.
a) What is the net force?
b) What is the acceleration of the mass?
a) What is the net force?
b) What is the acceleration of the mass?
Answers
MathMate
Resolve the forces to the direction of travel
F=2*40*cos(35)
=65.53 N
Fnet = 65.53-20
= 45.53 N
For acceleration, use Fnet = ma
a=Fnet/m
=45.53/15
= 3.03 m/s²
F=2*40*cos(35)
=65.53 N
Fnet = 65.53-20
= 45.53 N
For acceleration, use Fnet = ma
a=Fnet/m
=45.53/15
= 3.03 m/s²