Asked by Paul
In a simple titration experiment how and why are the results reproducible?
Answers
Answered by
bobpursley
This reminds me of the question of why a teacher counts the children in her class over and over, yet keeps getting the same number. Actually, the reasons are the same.
Answered by
Anonymous
suppose you wanted to dissolve 106 g of Na2co3 in enough H2O to make 6.00L of solution.
a) what is the molar mass of Na2CO3 ?
b) what is the molarity of this solution ?
a) what is the molar mass of Na2CO3 ?
b) what is the molarity of this solution ?
Answered by
DrBob222
Mass Na2CO3 = 106 grams.
moles Na2CO3 in 106 g = 106/106 = 1 mole.
b), M = moles/L = 1/6 = ??
moles Na2CO3 in 106 g = 106/106 = 1 mole.
b), M = moles/L = 1/6 = ??
Answered by
Anonymous
.166
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