Asked by Janey
Find the derivative of y=(2x²+x)²°°.
Answers
Answered by
drwls
Use the chain rule. Let 2x^2 +x = u(x)
y = u^200
dy/dx = dy/du * du/dx
dy/dx = 200*(2x^2 +x)^199 *(4x+1)
y = u^200
dy/dx = dy/du * du/dx
dy/dx = 200*(2x^2 +x)^199 *(4x+1)
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