Asked by kathryn
How many atoms of element "R" are present in 55.80 g of (AH3)4(R2O3)4 (molar mass = 478.17 g/mol)?
Please help. I've tried going (g of molecule/mol)x(1 mol of molecule/ 55.80g)but I'm not really sure what to do with this.
Please help. I've tried going (g of molecule/mol)x(1 mol of molecule/ 55.80g)but I'm not really sure what to do with this.
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