Leg traction is applied to a patient's leg as shown in the figure below. If the physician has requested a 33 N force to be applied to the leg, and the angle is θ = 60 degrees. what mass m must be used for the object hanging from the massless cable?

Question

Image of traction: please just type the dots as period oi53(dot)tinypic(dot)com/2a0b7yx(dot)jpg 

I thought the solution for this was just W = Tsin60 but apparently I am wrong. Please explain to me how to solve this. Thank you!

Answer 1

T-Fgsintheta=0
Fextsintheta-T=0
T=Fextsintheta
T=(33)(sin60)
T=28.58N

T-Fgsintheta=0
Fgsintheta= 28.58
m(sintheta)=28.58/9.8
m=3.367 kg

I think its right.