Asked by Guy
                "How fast is the area of the triangle formed by the ladder, the house, and the ground when the base of the ladder is 7 ft. away from the wall? 
Given
h=24ft.
dh/dt=-7/12ft. per sec.
b=7 (base)
db/dt=2ft. per sec.
d/dt[A=1/2bh]
How would you derive this with respect to time?
            
        Given
h=24ft.
dh/dt=-7/12ft. per sec.
b=7 (base)
db/dt=2ft. per sec.
d/dt[A=1/2bh]
How would you derive this with respect to time?
Answers
                    Answered by
            bobpursley
            
    A= 1/2 bh
dA/dt= 1/2 hdh/dt + 1/2 bdb/dt
compute, you have h, dh/dt, b, db/dt
    
dA/dt= 1/2 hdh/dt + 1/2 bdb/dt
compute, you have h, dh/dt, b, db/dt
                    Answered by
            Guy
            
    thanks
    
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