Question

f(x) = -4(x+2)(x - 5)^3
- 2, multiplicity 1, touches the x-axis and turns around; 5, multiplicity 3, touches x-axis and turns around

I left (x+2) out of the equation. Can you explain to me these type of problems, I only understand a little bit of it.

Answer 1

You have it right, if another x+2 is in the equation twice. Your understanding of odd and even funcions, and roots, is ok.