Asked by Sasha
finf y'' by implict differentiation
√x + √y = 1
√x + √y = 1
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Answered by
MathMate
√x+√y = 1
differentiate with respect to x:
1/(2√x) + (1/2√y) dy/dx =0
Substitute √y by 1-√x:
1/(2√x) + (1/2(1-√x)) dy/dx =0
Solve for dy/dx.
differentiate with respect to x:
1/(2√x) + (1/2√y) dy/dx =0
Substitute √y by 1-√x:
1/(2√x) + (1/2(1-√x)) dy/dx =0
Solve for dy/dx.
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