Asked by xiong
68 % of kids watch tv daily. out of 12 kids what is the probability that:
a. Exactly six kids watch tv daily
b. Six or less kids watch tv daily
c. Seven or more kids watch tv daily
d. Find the mean for the distribution
a. Exactly six kids watch tv daily
b. Six or less kids watch tv daily
c. Seven or more kids watch tv daily
d. Find the mean for the distribution
Answers
Answered by
Reiny
This is a case of binomial distribution
Prob(watching) = .68/100 = 17/25
prob(not watching) = 8/25
a) Prob(exactly 6 out of 12 watching)
=C(12,6)(17/25)^6(8/25)^6 = ....
b) prob(6 or less)
= Prob(exactly 1) + Prob(exacly 2) + prob(exactly 3) + .. prob(exactly 6)
= C(12,1)(17/25)(8/25)^11 + C(12,2)(17/25)^2(8/25)^10 + .. + C(12,6)(17/25)^6(8/25)^6
do the others the same way
hope you have a good calculator.
Prob(watching) = .68/100 = 17/25
prob(not watching) = 8/25
a) Prob(exactly 6 out of 12 watching)
=C(12,6)(17/25)^6(8/25)^6 = ....
b) prob(6 or less)
= Prob(exactly 1) + Prob(exacly 2) + prob(exactly 3) + .. prob(exactly 6)
= C(12,1)(17/25)(8/25)^11 + C(12,2)(17/25)^2(8/25)^10 + .. + C(12,6)(17/25)^6(8/25)^6
do the others the same way
hope you have a good calculator.
Answered by
xiong
We can use excel for this. do you know how I would set it up in excel?
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