Asked by Jack
Find the 1st derivative of the function:
y = 1/4 sin^2 (2x)
So confused...
y = 1/4 sin^2 (2x)
So confused...
Answers
Answered by
MathMate
dy/dx
=(1/4)d(sin^2(2x))/d(sin(2x))*d(sin(2x))/dx
=(1/4)*2sin(2x)*cos(2x)*2
=sin(2x)cos(2x)
=(1/2)sin(4x)
=(1/4)d(sin^2(2x))/d(sin(2x))*d(sin(2x))/dx
=(1/4)*2sin(2x)*cos(2x)*2
=sin(2x)cos(2x)
=(1/2)sin(4x)
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